1.) find g of f(x) if f(x)= x^2 + 3x and g(x)= 2x -1 2.) b= log^3 7?
for the first part:
to find g of f(x), just substitute the whole expression of f(x) in place of x in g(x), thus giving you - 2x^2+6x-1
for the second part, I'm assuming you mean find log 3 base 7:
in which case, the answer is given by (log 3 base 10)/(log 7 base 10).
the rule here is log a base b = (log a base c)/(log b base c), where c can be any base you are comfortable with
1) if you mean...