**Question:**i can do it in deciamal form but i dont know how to do it in radical from. in decimal from its -0.12915 how do i convert this number into a radical

(5x - 2)^2 = 7

Take the square root of both sides:

sqrt[ (5x - 2)^2 ] = sqrt[ 7 ]

5x - 2 = sqrt[ 7 ]

Now, add 2 to both sides:

5x - 2 + 2 = sqrt[ 7 ] + 2

5x = sqrt[ 7 ] + 2

Divide both sides by 5:

5x / 5 = (sqrt[ 7 ] + 2) / 5

x = (sqrt[ 7 ] + 2) / 5

---------------------

You can check your answer by

converting the radical form to decimal:

x = (sqrt[ 7 ] + 2) / 5

x = ( ± 2.64575 + 2) / 5

x = ( ± 2.64575 + 2) / 5

x = 4.64575 / 5 = 0.92915

and

x = ( - 2.64575 + 2) / 5

x = ( - 0.64575 + 2) / 5 = 0.12915

Good luck in your studies,

~ Mitch ~

(5x-2)^2=7

5x - 2 = sq root(7)

5x = sq rt(7) + 2

x = [ sq rt(7) + 2 ] / 5

x = the square root of 7, minus 2, all over 5

(5x-2)=sqrt(7)

5x=sqrt(7) + 2

x= [sqrt(7) + 2]/5 (radical form)

x = 0.92915 (decimal form)

there are two roots you :

(5x-2)^2=7

25x^2-2.2.5x+4=7

25x^2-20x-3=0

in radical form one is : ( 2+ sq rt ( 7) ) / 5

and the second one : ( 2- sq rt ( 7) ) / 5

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