**Question:**find the equation of a line containing the given point and having the given slope

Well, the equation is: y = mx + b

The slope is m: 5/8

We need to find the y-intercept, b.

Substitute 4 for x and 9 for y. So your equation now looks like:

9 = (5/8)(4) + b

Simplified, the equation is:

9 = 20/8 + b or 9 = 2 1/2 + b

We now have to solve for b:

b = 9 - 2 1/2

So, b = 6 1/2 or 6.5

The final slope-intercept equation is:

y = 5/8x + 6 1/2

x-y-23/2=0

(x,y) = (4,9). when x = 4, y = 9

y = mx + b

y = (5/8)x + b

substitute x = 4 and y = 9 to find b...

9 = (5/8)(4) + b

9 = 5/2 + b

b = 13/2

ANSWER... y = (5/8)x + 13/2

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