# (5x-2)^2=7 solve in radical form?

Question:i can do it in deciamal form but i dont know how to do it in radical from. in decimal from its -0.12915 how do i convert this number into a radical

(5x - 2)^2 = 7

Take the square root of both sides:
sqrt[ (5x - 2)^2 ] = sqrt[ 7 ]
5x - 2 = sqrt[ 7 ]

Now, add 2 to both sides:
5x - 2 + 2 = sqrt[ 7 ] + 2
5x = sqrt[ 7 ] + 2

Divide both sides by 5:
5x / 5 = (sqrt[ 7 ] + 2) / 5
x = (sqrt[ 7 ] + 2) / 5

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converting the radical form to decimal:
x = (sqrt[ 7 ] + 2) / 5
x = ( ± 2.64575 + 2) / 5

x = ( ± 2.64575 + 2) / 5
x = 4.64575 / 5 = 0.92915
and
x = ( - 2.64575 + 2) / 5
x = ( - 0.64575 + 2) / 5 = 0.12915

~ Mitch ~
(5x-2)^2=7

5x - 2 = sq root(7)

5x = sq rt(7) + 2

x = [ sq rt(7) + 2 ] / 5

x = the square root of 7, minus 2, all over 5
(5x-2)=sqrt(7)
5x=sqrt(7) + 2
x= [sqrt(7) + 2]/5 (radical form)
x = 0.92915 (decimal form)
there are two roots you :
(5x-2)^2=7
25x^2-2.2.5x+4=7
25x^2-20x-3=0

in radical form one is : ( 2+ sq rt ( 7) ) / 5
and the second one : ( 2- sq rt ( 7) ) / 5