(2x-2y)(3y+3z)=?

Answers:
use FOIL -Firsts, Outside,Insides,Lasts.
then

(2x-2y)(3y+3z)

F = 2x * 3y = 6xy
O = 2x *3z = 6xz
i = - 2y * 3y = 6y^2
L = -2y + 3z = -6yz

so combine em all:

6xy+6xz + 6y^2 -6yz

that's it

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FOIL it! Multiply first term, outside terms, inside terms, last terms. Mulitpy the coefficient. So first term is 6xy+.

You can go from there! I know it! :p

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if you're suppose to factorise it:
6xy+6xz-6y2-6yz

something like that

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(2x-2y)(3y+3z)=
6xy+6xz-6y^2-6yz

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use FOIL

6xy+6xz-6y^2-6yz

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=6(x-y)(y+z)= 6(xy+xz-y^2-yz)= 6xy+6xz-6(y^2)-6yz

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(2x-2y)(3y+3z)
= 6xy + 6xz - 6y^2 - 6yz

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