**Question:**conti..20% in the given mixture?

choice

a)5.5 litres

b)6.5 litres

c)6 litres

d)6.25 litres

e)6.75 litres

10% of 50L is 5L

a) 5.5L + 5L = 10.5L of 55.5L = 10.5%

b) 6.5L + 5L = 11.5L of 56.5L = 20.4%

c) 6L + 5L = 11L of 56L = 19.6%

d) 6.25L + 5L = 11.25L of 56.25L = 20.0%

e) 6.75L + 5L = 11.75L of 56.75L = 20.7%

Pick the closest answer

You know, there is a mathematics forum for homework help.

the ans is d 6.25litres

let the amt. of water added be x

since there is no change in the amt. of milk , equate the values i.e.

45 = 80/100 x (50+x)

calculate x

hi,

the answer is d)6.25 liters....

the reason is initially the % of water is 10% there fore in 50 liters of mixture there consists 5 liters of water.. to make it in to 20 % of water let us suppose we need to add 'x' liters of water, then (50+x)*20=5+x // since initially water in 50 liters is 5

by solving u get x=6.25 and thats ur answer.

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