**Question:**find an equation of the line containing the given point and given slope

y= -3x-2

-3x-y-6=0

y=-3x -6

u know m represents the slope of the equation which is -3

then put that into the slope intercept form: y=mx +b

it would look like y=-3x + b

now evaluate the value of the point (-2,0) to the equation y=-3x + b

it would be: 0= -3(-2) +b

0= 6 +b

move 6 to left

-6 = b

substitute b in the equation with the number

y= -3x -6

Therefore, the answer is y= -3x -6

DaMn i just finished my exams and already forgot the formulae wait i'll get my book :)..yea use the formulae

(y-y1)=m(x-x1)

ie . y minus y to the 2nd point that is 0 =m<slope>multiplied by 1st that is <-2>...

answer is 3x+y+6=0

...

:)

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